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Important information for all: Copyright basics for Web authors and users by Jukka Korpela
| Cable Kind | Bandwidth | Cost | Purpose | Distance(s) | Problem |
|---|---|---|---|---|---|
| Twisted Pair (telephone) | 1Mbps | Low | Telephone | 1-5 km | Easily interrupted Easily interfered |
| Twisted Pair (network) | 100-1000 Mbps | Low | Computer networks | 100m | Easily interrupted Easily interfered |
| Coaxial cable | 10Mbps | Low | LAN | 500m | Terminator needed Thick cable |
| Coaxial cable | 1-2 Gbps | Low | Backbone | 1 km | Easy to eavesdrop |
| Optical fiber | 10 Gbps | High | Connecting Network | Tens of Kms | Ring Topology Expensive Easily damaged Difficult to repair |
| Radio wave | Up to 10Mbps, depending on frequency band | Low | Mobile | X*10Km | Easily influenced by weather |
| Microwave | Up to 100 Mbps, depending on frequency band | Low | Mobile, WLAN, Bluetooth | about 80 kms with 100 m towers | Easily influenced by weather, requires line of sight |
When we use different kinds of cable connecting together, due to the different impedance, the electrical signal will be reflected back at the interface of two different media. Then the transmission will fail. The bandwidth of the low quality telephone cables is significantly lower than proper LAN cables.
According to Nyquist's theorem: R_MAX=2Hlog(2)V
bits/sec=2*4000*log(2)4=16kbps
According to Shannon's theorem: R_max=hlog(2)(1+S/N)
bit/sec=4000*log(2)(1+10)=13.8kbps
Total Attenuation=4.6dB-3.8dB+5.2dB=6dB
Total Attenuation=10log(2)(P1/P2)
P1=p2*10^(6dB/10)=796mW